(20/(x^2)-4)-(5/x-2)=(7/x+2)

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Solution for (20/(x^2)-4)-(5/x-2)=(7/x+2) equation: 



(20/(x^2)-4)-(5/x-2)=(7/x+2)

We move all terms to the left:

(20/(x^2)-4)-(5/x-2)-((7/x+2))=0



Domain of the equation: x^2-4)!=0

x∈R





Domain of the equation: x-2)!=0

x∈R





Domain of the equation: x+2))!=0

x∈R



We get rid of parentheses

20/x^2-5/x-((7/x+2))-4+2=0

We calculate fractions

We do not support expression: x^4

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